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My name is Ann [436]
3 years ago
12

Please does someone know the answer???

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

Square root of 65

Its c

Please make me the brainliest because I havent got even 1 yet :(



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Answer:

sin70° = x/6

Step-by-step explanation:

When we draw out our picture and triangle, we should see that our angle is on the ground 70°, the height <em>x</em> is across from the angle and is the vertical leg up, and that our hypotenuse is equal to 6:

sin70° = x/6

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Dvinal [7]
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What is estimate 4.23-2.51
ruslelena [56]
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Please answer it correctly and please show work please help me I need it
tamaranim1 [39]

Answer:

the equation is

y = 0.75x

And,  the constant of proportionality is 0.75

Step-by-step explanation:

The computation is shown below:

Given that

4y = 3x

And,

12y = 9x

Here the equation that represent proportional relationship is

4y = 3x

Divide both sides by 4

y = 3x ÷ 4

Now

12y = 9x

divides both sides by 12

y = 9 ÷ 12x

y = 3 ÷ 4x

y = 0.75x

so the equation is

y = 0.75x

And,  the constant of proportionality is 0.75

4 0
3 years ago
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
3 years ago
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