In order to figure this out you need to use
Descartes Rule. I attached a picture showing Descartes Rule. If the signs changes for when x is positive then the number of times it changes are the possible positive solution. If the sign changes when x is negative then the number of times it changes are the possible negative solutions. With that said the answer is A. View the picture I have attached for the possible + - and imaginary solutions.
Answer = A) One possible positive solution.
Given that:
f(x) = -2x²-2x+10
f(2) = -2(2)²-2(2)+10
= -2(2*2) - 4 + 10
= -2(4) - 4 + 10
= -8 - 4 + 10
= -12 + 10
= -2 Ans.
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Similar Question
Given f(x) = 1/2x - 5, find f^-1(x) a. f^-1 (x) = -2x+10 b. f^-1(x) = 2x+5 c. f^-1(x) = 2x-10 d. f^-1(x) = 2x+10...
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Answer:
c
Step-by-step explanation:
For an inverse function you take f(x) and turn that to y then you switch x and y. So you should start off with y= 5x -8. so then you switch x and y so x= 5y - 8. So then you solve. You subtract 8 from both sides and divide by 5 and you get F(x) inverse = x + 8/5
The answer is d because quotient means the outcome of a division between two numbers. So therefore it has to be a division equation, which is d.
Answer:
(a) discriminant is positive, 76
(b) the above tells you there are two real roots
Step-by-step explanation:
the discriminant is 'b² - 4ac'
3x² - 2x - 6 = 0 ∴ a = 3, b = -2, c = -6
(-2)² - 4(3)(-6) = 4 + 72
