Answer:
c≥2(x-2) ÷ 5
Step-by-step explanation:
5c+3≥6x-8
5c ≥6x-8-3
5c≥6x-12
c≥(6x-12) ÷ 5
c≥ 2(x-2) ÷5
The zeros of the function are x=2,-9
Given function is

now we need to find the value of k such that function f(x) continuous everywhere.
We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.
So we just need to find both left and right hand limits then set equal to each other to find the value of k
To find the left hand limit (LHD) we plug x=-4 into 3x+k
so LHD= 3(-4)+k
To find the Right hand limit (RHD) we plug x=-4 into

so RHD= 
Now set both equal





k=-0.47
<u>Hence final answer is -0.47.</u>
Answer: 123 IS
Step-by-step explanation:
Answer:
40%
Step-by-step explanation:
40 is 40% of 100, you don't need a calculator for that, so, it's a 40% increase
hope this helps:)