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Katen [24]
1 year ago
12

Helpp- question linked below

Mathematics
1 answer:
Ksenya-84 [330]1 year ago
5 0

Answer:

Ann = 67 stickers

Josh = 60 stickers

Claire = 30 sickers

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Simplify 7x²+3x-5x²-10x
solmaris [256]

Answer:

2x²-7x

Step-by-step explanation:

7x²-5x²=2x²

10x-3x=7x

3 0
3 years ago
Let N be the universal set and A, B, C, D be its subsets given by A={x:xisaevennaturalnumber},B={x:xNandxisamultipleof3} C={x:x
Svet_ta [14]

Answer:

A^{'} = {1,3,5,7,9,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = {1,2,3,4,5}

D^{'} = {10,11,12,13,14,15,......}

Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

Set A, Set B, Set  C, Set D are subsets of Universal set.

A = {x:x is even natural numbers} = {2,4,6,8,10,.....}

B = {x:x ∈ N and x is a multiple of 3} = {3,6,9,12,15,....}

C = {x:x∈ N and x < 5} = {6,7,8,9,10,.....}

D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

A^{'} = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

A^{'} = {1,3,5,7,9,....}

B^{'} = U-B =  {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

C^{'} = {1,2,3,4,5}

D^{'} = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

D^{'} = {10,11,12,13,14,15,......}

8 0
3 years ago
Use the inequality 18 &lt; -3(4x - 2)<br> Solve the inequality for x. <br> Show your work.
IrinaVladis [17]

Answer:

x > -1

Step-by-step explanation:

Simplify the inequality using the distributive property (multiply the term outside the bracket with each number inside the bracket). Then, isolate 'x' by performing the reverse operations for every number that's on the same side as 'x'. (Reverse operations 'cancel out' a number.)

18 < -3(4x - 2)           Expand this to simplify

18 < (-3)(4x) - (-3)(2)             Multiply -3 with 4x and -2

18 < -12x + 6               Start isolating 'x'

18 - 6 < -12x + 6 - 6                 Subtract 6 from both sides

18 - 6 < -12x                  '+ 6' is cancelled out on the right side

12 < -12x                    Subtracted 6 from 18 on the left side

12/-12 < -12x/-12                    Divide both sides by -12

12/-12 < x                    'x' is isolated. Simplify left side

-1 < x                    Answer

x > -1             Standard formatting puts variable on the left side

6 0
3 years ago
Jay Spring pays $350.00 annually for his health insurance. This is 1/3 of the total cost of the premium; his company pays the re
WINSTONCH [101]

Q: How much did Jay have to pay excluding his share of the insurance premium?

A: $1800+$200 = $2000

Q: How much did Jay's company pay for his insurance premium?

A: $700. If Jay's $350 is 1/3 of the premium , then Jay's company pays 2*$350=$700 as rest of his premium.

Q: Jay paid 10% and the plan paid 90% beyond the deductible. How much did Jay's insurance company pay total?

A: Jay's insurance company paid $16200. Given that Jay paid $1800 beyond his deductible of $200 (and that is 10% of the actual cost) means that his plan (insurance company) paid 90%=9*$1800=$16200.

Q: How much did Jay have to pay total, including his share of the premium?

A: Jay paid $2350. He paid $200 deductible + $1800 beyond deductible + $350 premium



8 0
3 years ago
Read 2 more answers
Use the recursive formula to answer the question.
scZoUnD [109]
You know a1.
So find a2, a3, and so on until a7.

a(1) = 12
a(2) = 16
a(3) = 20
a(4) = 24
a(5) = 28
a(6) = 32
a(7) = 36
Each is 4 more than the previous.
4 0
3 years ago
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