The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation 
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2=0
=> =0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
#SPJ1
The dollar didn't go anywhere! The question isn't correct because the money the bellhop stole is supposed to be subtracted, not added. So if we subtract $2 we have $25, and that's how much money the owner got, the men got $3 back and the bellboy got $2.
So the owner gets $25, the men get $3 and the bellboy gets $2, and that equals 30.
The answer is probably one of the followig:
Natural Number
Whole Number
Integer
Rational
or Real
