<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<h3>
Answer: (-3, 0)</h3>
Explanation:
Point N is at (1,3)
We apply the rule 
which will translate the point 4 units to the left and 3 units down.
The old x coordinate x = 1 becomes x-4 = 1-4 = -3
The old y coordinate y = 3 becomes y-3 = 3-3 = 0
The point N(1,3) moves to N ' (-3, 0)
Answer:
90^
Step-by-step explanation:
Answer:
0.5
Step-by-step explanation:
42 divided by 2/3 = 7
7 divided by 2/7 = 0.5
