Answer:
12(m -5) = 540
Step-by-step explanation:
The left side of the equation is in the form of a product. A suitable product is ...
(calories/minute) × (minutes jogging) = (calories burned)
If m represent Anzelm's total minutes, then m-5 will represent the number of minutes actually jogging. This is what goes inside parentheses, so we have ...
(12 calories per minute) × ((m -5) minutes) = 540 calories
Leaving off the units, which we know are consistent, we have ...
12 (m -5) = 540
Answer: n= −3
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
8(4n+3)=−72
(8)(4n)+(8)(3)=−72(Distribute)
32n+24=−72
Step 2: Subtract 24 from both sides.
32n+24−24=−72−24
32n=−96
Step 3: Divide both sides by 32.
32n/32 = −96/32
n=−3
1,000 x 2= 2,000
2,000/1=2,000
2,000 - 29 = 1,971
Answer:
8x+9
Step-by-step explanation:
Add the like terms together.
3x+9+4x+x = 8x+9
Answer:
The answer should be A.
.
Step-by-step explanation:
Start with the second inequality, which is more straightforward than the first. Add
to both sides of this equation to separate
from the numbers:
. The direction of the inequality sign shall stay the same.
.
On the other hand, simplifying the first inequality takes a bit more work. Start by dividing both sides by
. However, keep in mind that dividing or multiplying both sides of an inequality with a negative number will invert the direction of the inequality sign. For example, the left-hand side of an inequality might have been greater than the right-hand side. When both sides are multiplied with a number less than zero, the new left-hand side would become smaller than the new right-hand side.
Because
is a negative number, dividing both sides of the first inequality inequality by
will turn the "greater-than" sign into a "less-than" sign.
The inequality used to be:
.
After dividing both sides by the negative number
, it becomes:
.
.
.
The question connected the two original inequalities with "or". Therefore, the conditions will be satisfied as long as either of at least one of the two inequalities is true. Note, that
is true whenever
is true. Therefore, any real number that is smaller than
will meet the requirements- not just those that are smaller than
.
The corresponding interval will be
.