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3 years ago

Select all the ratios equivalent to 16/1424:2132:2821:7

Mathematics

2 answers:

sasho [114]3 years ago

6 0

The answers are 24:21 and 32:28

pashok25 [27]3 years ago

5 0

Answer:

First and second. 24:21, 32:28

Step-by-step explanation:

Just do it. Hope I helped you!;)

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Mr. Con makes punch by mixing 10.6 L of apple juice 0.6 L of oranges and 8 L of Ginger ale. He pours the mixture equally into 6

sattari [20]

Answer:

3.2

Step-by-step explanation:

For this we need to get the entire volume of the mixture. We get it by summing each quantities:

Vol = 10.6 + 0.6 + 8 = 19.2 L

So, we have 19.2 L for 6 bowls.

For getting the punch of each bowl we just need to divide this volume between the 6 bowls:

19.2 / 6 = 3.2 L

So, each bowl has 3.2 L

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3 years ago

The amount of blueberries picked, in pounds, varies directly as the number of hours worked. After

OverLord2011 [107]

Answer:

Step-by-step explanation:

3 pounds were picked per hour

4 0

3 years ago

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Some please help and explain the steps. Tysmmmmm

-Dominant- [34]

Answer:

since angle B and angle C contains the same arc AD. set the angles equal

11x-3=8x+15

x=6

so the angle has a measure of 63 degrees

the central angle is the angle of the arc

and it is always 2 times the angle that we just that contains the arc but does touches the end of the circle.

so its 63 *2 =126 degrees.

5 0

3 years ago

Plz answer i will really apreciate it :) 50 points

hoa [83]

Answer:

b or c

Step-by-step explanation:

7 0

3 years ago

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2. The National Safety Council routinely analyzes the benefit of seat belt use on driver safety. Their data showed that among 28

JulijaS [17]

Answer:

We conclude that there is difference in the proportion of deaths between the 2 groups.

Step-by-step explanation:

We are given that among 2823 drivers not wearing seat belts, 31 died as a result of injuries, and among 7765 drivers wearing seat belts 16 were killed.

Let $p_1$ = proportion of deaths when drivers were not wearing seat belts.

$p_2$ = proportion of deaths when drivers were wearing seat belts.

So, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no difference in the proportion of deaths between the 2 groups}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is difference in the proportion of deaths between the 2 groups}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of deaths when drivers were not wearing seat belts = $\frac{31}{2823}$ = 0.011

$\hat p_2$ = sample proportion of deaths when drivers were wearing seat belts = $\frac{16}{7765}$ = 0.002

$n_1$ = sample of drivers not wearing seat belts = 2823

$n_2$ = sample of drivers wearing seat belts = 7765

So, the test statistics = $\frac{(0.011-0.002)-(0)}{\sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} } }$

= 4.438

The value of z test statistics is 4.438.

Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is difference in the proportion of deaths between the 2 groups.

Also, Margin of error (E) = $1.96 \times \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} }$

= $1.96 \times \sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} }$

= 0.00397

5 0

3 years ago

Select all the ratios equivalent to 16/1424:2132:2821:7​

Select all the ratios equivalent to 16/1424:2132:2821:7