Vertical asymptotes happen at x=a if the function is undefined at x=a.
This is a rational functions, and rational functions are not defined when the denominator is zero, since you can't divide by zero.
In this case, the denominator is zero if
And thus the function has a vertical asymptote at x= -3/2
Answer:
C
Step-by-step explanation:
That would be an isosceles triangle, therefore, acute. All angles measure 60, therefore being acute. I'm not 100% sure though.
The time when the maximum serum concentration is reached is obtained by equating the derivative of C(t) to 0.
i.e. dC(t)/dt = 0.06 - 2(0.0002t) = 0.06 - 0.0004t = 0
0.0004t = 0.06
t = 0.06/0.0004 = 150
Therefore, the maximum serum concentration is reached at t = 150 mins
The maximum concentration = 0.06(150) - 0.0002(150)^2 = 9 - 0.0002(22,500) = 9 - 4.5 = 4.5
Therefore, the maximum concentration is 4.5mg/L
Answer:
b=2A/h-a
Step-by-step explanation:
A=1/2h(a+b)
a+b=A/(1/2h)
a+b=A/(h/2)
a+b=(A/1)(2/h)
a+b=2A/h
b=2A/h-a
Answer:
A) 11% B) 60
Step-by-step explanation:
(for A) if you add all the "Frequency" it adds up to 100, so we don't need to do any maths for that because we already have our 100% right there. So less maths to do because if that right there is already the whole, then the frequency of it is the % out of 100%
(for B) If you take your calculator and do 12 x 500, you get 6,000, press the "%" button and it gives you the percent of what that probability of getting 6 after rolling 500 times with its sent frequency
(took me a minute to learn this this for you... by that i mean i messed around with my calculator for like 3 minutes) Hope this is right.