Answer:
False
Step-by-step explanation:
Answer: 441
Step-by-step explanation:
21 x 21 = 441
The first 5 terms in an arithmetic sequence is 4,2,0,-2,-4
Explanation:
The general form of an arithmetic sequence is

where a denotes the first term of the sequence, d denotes the common difference.
Here a = 4 and d = -2
To determine the consecutive terms of the sequence, let us substitute the values for n.
To find the second term, substitute n = 2 in the formula 

Simplifying,

Similarly,
For n = 3,

For n = 4,

For n = 5,

Thus, the first 5 terms of the arithmetic sequence is 4,2,0,-2,-4
Answer:

Step-by-step explanation:

Apply sum of cubes formula: 

