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netineya [11]
3 years ago
14

Xy=80 solve log x- log y=1

Mathematics
1 answer:
Basile [38]3 years ago
6 0

Question: Solve for x and y in the equation.

xy=80 and log x - 2 log y =1

Answer:

x = 40, y = 2

Step-by-step explanation:

xy = 80.......................... Equation 1

logx-2logy = 1

logx-logy² = 1

Applying the laws of logarithm,

log(x/y²) = log10

x/y² = 10

x  = 10y²......................... Equation 2

Substitute the value of x in therms of y equation 2 into equation 1

10y²(y) = 80

10y³ = 80

y³ = 8

y = \sqrt[3]{8}

y = 2.

Substitute the value of y into equation 1

2x = 80

x = 80/2

x = 40

Therefore,

x = 40, y = 2

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2b/3+6=24 Need help not good at math so this will help.
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<u><em>b=108 is the correct answer.</em></u> First you had to multiply by 9 from both sides of equation, and it gave us, \frac{9*2b}{3+6}=24*9. And then simplify, and it gave us, 2b=216. You can also divide by 2 from both sides of equation, and it gave us, \frac{2b}{2}=\frac{216}{2}. And finally simplify, and it gave us the answer is 216/2=108, or <u><em>b=108 is the correct answer.</em></u> Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

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Factorise and Solve the quadratic equations below.<br><br> x^2+11x+24=0
Fudgin [204]
X² + 11x + 24 = 0

24*1 = 24

We think of 2 numbers that multiply to give 24 and add up to give 11

The 2 numbers are 8 and 3.

8*3 = 24      and  8 + 3 = 11

So the 11x in    x² + 11x + 24 = 0

Replace 11x with (3x + 8x)

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x² + 3x + 8x + 24 = 0            Factorize.

x(x + 3) + 8(x + 3) = 0

(x + 3)(x + 8) = 0

That means:

x + 3 = 0    or  x + 8 = 0

x = 0 - 3                x = 0 - 8

x = -3        or        x = -8


Therefore:  x² + 11x + 24 = 0  is (x + 3)(x + 8) = 0   and x = -3 or x = -8

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