Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem
t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).
So t = √(3r^2) = √3r answer.
Answer:
28.26m^2 (aka. 28.26 meters squared)
Step-by-step explanation:
The area of a circle is A=pi*r^2 where r is the radius of the circle.
Since r=3, then A=pi*3^2=9pi=28.26
Therefore, the area of the merry-go-round is 28.26 square meters
Answer:
PQ:80
QR:160
PR:120
Step-by-step explanation:
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<em>hope it helps </em>
<em>have a great day!!</em>
Answer is a if I am not mistaken