Question

Solve system of equations 5x+2y=29, 5x-2y=41

Answer 1

Solving $5x+2y=29,5x-2y=41$ we get x=7 and y= -3

Step-by-step explanation:

We need to solve the following systems of equations:

$5x+2y=29\\5x-2y=41$

Let:

$5x+2y=29\,\,\,eq(1)\\5x-2y=41\,\,\,eq(2)$

Adding eq(1) and eq(2)

$5x+2y=29\\5x-2y=41\\-------\\10x=70\\x=70/10\\x=7$

So, value of x=7

Putting value of x in eq(1) to find value of y:

$5x+2y=29\\5(7)+2y=29\\35+2y=29\\2y=29-35\\2y=-6\\y=-6/2\\y=-3$

So, value of y = -3

So, Solving $5x+2y=29,5x-2y=41$ we get x=7 and y= -3

Keywords: Solving system of Equations

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