Y=-2x+6 3y-x+3=0 Solving systems using substitution
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First we need to write the factors of the polynomial. In order for 1, 4, and -3 to be roots, they need to be the x values that make the polynomial equal 0.
(x - 1) = 0
That would be the factor for x = 1 because when we plug 1 in for x we get 1 - 1 which equals 0.
Multiply all the factors together.
(x-1)(x-4)(x+3)=0
Now FOIL.
(x - 1) = 0
That would be the factor for x = 1 because when we plug 1 in for x we get 1 - 1 which equals 0.
Multiply all the factors together.
(x-1)(x-4)(x+3)=0
Now FOIL.
Answer:
<h2>x = 140, y = 80</h2>Step-by-step explanation: