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Svetllana [295]
3 years ago
8

Y=-2x+6 3y-x+3=0 Solving systems using substitution

Mathematics
1 answer:
Murljashka [212]3 years ago
5 0

You can "plug in" the value for y from the top eq in the bottom one:

3(-2x+6) - x + 3 = 0

Simplify:

-6x + 18 - x + 3 = 0

-7x + 21 = 0

-7x = -21

x = 3

y = -2*3+6 = 0

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1. Delia purchased a new car for $23,350. This make and model straight line depreciates to zero after 13 years.
frosja888 [35]

Answer:

a. y-intercept = 23350 and x-intercept = 13

b. m = -\frac{23350}{13}

c. y = -\frac{23350}{13}x + 23350

Step-by-step explanation:

Given

Years = 13

Total\ depreciation = \$23350

Solving (a): The x and y intercepts

The y intercept is the initial depreciation value

i.e. when x = 0

This value is the value of the car when it was initially purchased.

Hence, the y-intercept = 23350

The x intercept is the year it takes to finish depreciating

i.e. when y = 0

From the question, we understand that it takes 13 years for the car to totally get depreciated.

Hence, the x-intercept = 13

Solving (b): The slope

The slope (m) is the rate of depreciation per year

This is calculated by dividing the total depreciation by the duration.

So:

m = \frac{23350}{13}

Because it is depreciation, it means the slope represents a deduction.

So,

m = -\frac{23350}{13}

Solving (c): The straight line equation

The general format of an equation is:

y = mx + b

Where

m = slope

b = y\ intercept

In (a), we have that:

y\ intercept = 23350

In (b), we have that:

Slope\ (m) = -\frac{23350}{13}

Substitute these values in y = mx + b

y = -\frac{23350}{13}x + 23350

<em>Hence, the depreciation equation is: </em>y = -\frac{23350}{13}x + 23350<em></em>

8 0
3 years ago
the temperature at noon is -4F. the temperature at 6:00pm is -12. what is difference between noon and 6:00pm temperature
uysha [10]

Answer:

8 degrees Fahrenheit

Step-by-step explanation:

4 0
4 years ago
A vase contains r roses and 6 tulips. Write two equivalent expressions for the total number of flowers in the vase.
Margaret [11]
Two equivalent fractions equations are
r + 6
6 + r <span />
5 0
3 years ago
Read 2 more answers
Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ
Allisa [31]

Answer:

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

8 0
3 years ago
M/n x p for m = 10, n = -5, and p = -2
Novay_Z [31]
M / n x p = 10/-5 x -2 = -2 x -2 = 4
6 0
3 years ago
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