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xxMikexx [17]
3 years ago
14

Which description would best explain what was happening during Kayla’s bath during interval C on the graph?

Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0
No I don't want your number.
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Two mechanics worked on a car. The first mechanic worked for
yuradex [85]
Create equations:
10X+15y=2575.
X+Y=210.
Solve for X: X=210-Y, and sub it into the other equation: 10(210-Y)+15Y=2575. Solve for Y: 2,100-10y+15y=2575, 5y=475, y=95.
Sub Y into the original problem: X+95=210. Solve: X=115.
The first mechanic charges $115 per hour and the second charges $95 :)
6 0
2 years ago
Read 2 more answers
HELP ASAP Solve for x. Show or explain your work.
irinina [24]

Answer:

x=4.5

Step-by-step explanation:

From AAA, both triangles in this figure are similar. Therefore, we can set up the following proportion:

\frac{x}{9}=\frac{x+3}{15} or \frac{x}{9}=\frac{3}{6}.

Cross-multiplying, we get:

6x=9(3),\\6x=27,\\x=\frac{27}{6}=\fbox{$4.5$}.

7 0
2 years ago
Justin completes 8 extra credit problems on the first day and then 4 problems each day until the worksheet is complete. There ar
Serhud [2]

Answer:

28-8-4x=0

x=5

5 days

Step-by-step explanation:

28-8=20 problems left

then 4 each day

3 0
2 years ago
Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?
alexgriva [62]

Answer:

x Superscript 9 Baseline (RootIndex 3 StartRoot y EndRoot)

OR x^9/(∛y)

Step-by-step explanation:

Given the indicinal equation

(x^27/y)^1/3

To find the corresponding expression, we will simplify the equation as shown:

(x^27/y)^⅓

= (x^27)^⅓/y⅓

= {x^(3×9)}^⅓/y⅓

= x^9/y⅓

= x^9/(∛y)

The right answer is x Superscript 9 Baseline (RootIndex 3 StartRoot y EndRoot)

6 0
2 years ago
Read 2 more answers
It is known that 10% of the calculators shipped from a particular factory are defective. What is the probability that exactly th
IRINA_888 [86]

Answer:0.0081  or 0.81%

Step-by-step explanation:

The required probability is P(3,5,0.1)= C5 3 * p^3*q^2, where

C5 3=  5!/3/2=4*5/2=10

p is the probability that one randomly selected calculator is defective= 10%=0.1

q is the probability that one randomly selected calculator is non-defective.

q=1-p=1-0.1=0.9

So P(3,5,0.1)= 10*0.1^3*0.9^2=0.01*0.81=0.0081

4 0
3 years ago
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