3x +2= 5x
-3x
2= 2x
/2
1= x
So first I got all the x’s on one side and the whole numbers on the other side. So we had 2 on one side and 2x on the other. From there we divided by the number of x’s which was 2 so we can get one x only. So 2/2= 1 so x =1
800000+4,000+80+2 you don’t need the zeros
If you would like to solve - 3 * a^2 - b^3 + 3 * c^2 - 2 * b^3, if a = 2, b = -1, c = 3, you can calculate this using the following steps:
a = 2, b = -1, c = 3
- 3 * a^2 - b^3 + 3 * c^2 - 2 * b^3 = - 3 * 2^2 - (-1)^3 + 3 * 3^2 - 2 * (-1)^3 = - 3 * 4 - (-1) + 3 * 9 - 2 * (-1) = - 12 + 1 + 27 + 2 = 18
The correct result would be 18.
interior angle of n-gon formula: 180 - ( 360 / n)
a 30 sided polygon, so in this case n = 30
so
interior angle = 180 - ( 360 / 30)
interior angle = 180 - 12
interior angle = 168
answer
168 degrees
Answer:
7miles
equations shown in work image below
work shown on the paper with more explanations because text is hard to write equations (sorry I used km but it is miles for your problem.)
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Step-by-step explanation:
For both d=r*t
Each bikes to others house and leave at the same time so for Tony,
11 = 30*t
t= 11/30 hours
for Gerry,
11 = 25*t
t= 11/25 hours
Comparing these, with LCD,
Tony's time is 55/150
Gerry's time is 66/150
So Tony got to Gerry's house 11/150 hours quicker than Gerry got to Tony's house.
Now they turn around and head back toward each other. If they leave at the same exact time, the elapsed time for each until they met would be the same so t (for tony) = t (for gerry), but Tony got a head start.
We start the stopwatch when Gerry turns around 11/150 hours after Tony has turned around. If Gerry's time to where they meet from Tony's house t(gerry), then Tony's time from Gerry's house is t(gerry) + 11/150