Find -3a2 - b3 + 3c2 - 2b3 if a = 2, b = -1, and c = 3

2 answers:

7 0

The first thing you want to do, is to substitute the given to the equation. It will look like this:
-3(2)2 + 3(3)2 -2(1)3.
Remember the MDAS method (Multiply, Division, Addition and Subtract.) So, you need to multiply all the numbers we have substitute in the equation.
-12 + 18 - 6.
Then, remember to add comes first and subtraction comes last. So, we need to add -12 and +18 that will lead to this:
+6 - 6
Since -12 is negative and +18 is postive, so if we’ll add them up it’s +6. It is positive since +18 is bigger than -12. The answer is zero (0.)

Studentka2010 [4]2 years ago

6 0

If you would like to solve - 3 * a^2 - b^3 + 3 * c^2 - 2 * b^3, if a = 2, b = -1, c = 3, you can calculate this using the following steps:

a = 2, b = -1, c = 3
- 3 * a^2 - b^3 + 3 * c^2 - 2 * b^3 = - 3 * 2^2 - (-1)^3 + 3 * 3^2 - 2 * (-1)^3 = - 3 * 4 - (-1) + 3 * 9 - 2 * (-1) = - 12 + 1 + 27 + 2 = 18

The correct result would be 18.

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a total of $21,000 is invested in two bonds that pay 4% and 7.5% simple interest. The bond with 7.5 % interest rate earned 6 tim

hjlf

21000=a+b
ax.075xt=6xbx.04xt
t cancels out
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4 0

2 years ago

Domain and range of the function and it’s inverse

sineoko [7]

Answer:

B (second table in list)

Step-by-step explanation:

The function is a quadratic with vertex and y-intercept at (0,-2). The parabola opens up meaning only y - values above -2 are a part of the function. Since range is the set of all y values, then the range is $y\geq -2$ .