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melomori [17]
2 years ago
8

3x+2=5x What is the answer for this solving equations with variables on each side

Mathematics
2 answers:
Yanka [14]2 years ago
6 0
3x +2= 5x
-3x
2= 2x
/2
1= x
So first I got all the x’s on one side and the whole numbers on the other side. So we had 2 on one side and 2x on the other. From there we divided by the number of x’s which was 2 so we can get one x only. So 2/2= 1 so x =1
marysya [2.9K]2 years ago
3 0

x=1 that the answer


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1. A soccer field has an area (A = LW) that is represented by the polynomial 1 point
matrenka [14]

Answer:

(x + 6)(x - 6)

Step-by-step explanation:

Given

See attachment for soccer field

Required

The possible dimension of the field

From the attachment, we have:

Area = x^2 - 36

Length = x +a

Width = x + b

So, we have:

Length * Width = Area

This gives:

(x + a)(x + b) = x^2 - 36

Express 36 as 6^2

(x + a)(x + b) = x^2 - 6^2

Express as difference of two squares

(x + a)(x + b) = (x + 6)(x - 6)

Hence, the dimension is: (x + 6)(x - 6)

6 0
2 years ago
What is the slope of f(x)=x^2+3 when x=-1 ?
irinina [24]
F(x)=(-1)^2+3
f(x)=1+3
f(x)=4

The slope is 0 because 4 is a constant.
8 0
3 years ago
Find The Area Of The Shape Shown Below
ruslelena [56]

Answer:42.55

Step-by-step explanation:

Les get the big boi out of the way first. We see that it is 3.5 by 9 and if we multiply we get 31.5. Next left triangle 2 by 2 so four but divided by 2 is 2. God so many  2's. So total is 33.5 so far. Next triangle is 2 by 5 soo  10 divided by 2 is 5. total is 38.5. Last dude in the middle. We know one side is two so we have to subtract here from the triangles which gets u the other side of 2 so 4. Total is 42.5

8 0
3 years ago
Read 2 more answers
Suppose brine containing 0.2 kg of salt per liter runs into a tank initially filled with 500 L of water containing 5 kg of salt.
Oliga [24]

Answer:

(a) 0.288 kg/liter

(b) 0.061408 kg/liter

Step-by-step explanation:

(a) The mass of salt entering the tank per minute, x = 0.2 kg/L × 5 L/minute = 1 kg/minute

The mass of salt exiting the tank per minute = 5 × (5 + x)/500

The increase per minute, Δ/dt, in the mass of salt in the tank is given as follows;

Δ/dt = x - 5 × (5 + x)/500

The increase, in mass, Δ, after an increase in time, dt, is therefore;

Δ = (x - 5 × (5 + x)/500)·dt

Integrating with a graphing calculator, with limits 0, 10, gives;

Δ = (99·x - 5)/10

Substituting x = 1 gives

(99 × 1 - 5)/10 = 9.4 kg

The concentration of the salt and water in the tank after 10 minutes = (Initial mass of salt in the tank + Increase in the mass of the salt in the tank)/(Volume of the tank)

∴ The concentration of the salt and water in the tank after 10 minutes =  (5 + 9.4)/500 = (14.4)/500 = 0.288

The concentration of the salt and water in the tank after 10 minutes = 0.288 kg/liter

(b) With the added leak, we now have;

Δ/dt = x - 6 × (14.4 + x)/500

Δ = x - 6 × (14.4 + x)/500·dt

Integrating with a graphing calculator, with limits 0, 20, gives;

Δ = 19.76·x -3.456 = 16.304

Where x = 1

The increase in mass after an increase in = 16.304 kg

The total mass = 16.304 + 14.4 = 30.704 kg

The concentration of the salt in the tank then becomes;

Concentration = 30.704/500 = 0.061408 kg/liter.

6 0
3 years ago
Ugh I’m kinda stuck someone can help me ?
lara31 [8.8K]

Answer:

To graph this line, move one of the points to positive three on the horizontal (side to side) line and negative six on the vertical (up and down) line. To get a slope of negative 1/2 you move down one point and right two points, and you continue until you reach the edge of the graph. Then you do the opposite on the way up (up one and left two).

Hope this helps!

3 0
2 years ago
Read 2 more answers
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