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3 years ago

I'm a factor of 20 but not a multiple of 5

2 answers:

8 0

Factor of 20: 1, 2, 4, 5, 10, 20
Multiple of 5: 5, 10, 15, 20, 25, ...

1, 2, and 4 are factors of 20 but are not multiples of 5.

lianna [129]3 years ago

4 0

2 is a factor of 20 and not a multiple of 5

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For the differential equations dydx=sqrt(y^2−36) does the existence/uniqueness theorem guarantee that there is a solution to thi

julsineya [31]

Answer:

1. (-4,6) there is no a solution to the equation through this point

2. (2,−6) there is no a solution to the equation through this point

3. (−5,39) there is a solution to the equation through this point

4. (−1,45) there is a solution to the equation through this point

Step-by-step explanation:

Using the existence and uniqueness theorem:

Let:

$F(x,y)=\sqrt{y^2-36} \\\\and\\\\\frac{\partial F}{\partial y} =\frac{y}{\sqrt{y^2-36} }$

Now, let's find the domain of $F(x,y)$ , due to the square root:

$y^2-36 \geq 0\\\\y^2\geq 36\\\\y \geq 6\hspace{12}or\hspace{12}y\leq-6$

So the domain of the function is:

$y \in R\hspace{12}y\geq6\hspace{12}or\hspace{12}y\leq-6$

Now, due to the fraction $\frac{\partial F}{\partial y}$ the denominator must be also different from 0, so:

$y^2-36\neq0\\\\y \neq \pm6$

So, the theorem tells us that for each $y_0\in R:\hspace{12}y_0>6\hspace{12}or\hspace{12}y_0$ there exists a unique solution defined in an open interval around $x_0$ .

1. (-4,6) there is no a solution to the equation through this point because $y_0=6$

2. (2,−6) there is no a solution to the equation through this point because

$y_0=-6$

3. (−5,39) there is a solution to the equation through this point because

$y_0>6$

4. (−1,45) there is a solution to the equation through this point because

$y_0>6$

6 0

3 years ago

Please help me I need help ASAP

never [62]

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7 0

3 years ago

Who's playing ml haha

svlad2 [7]

Answer:

joe mama

Step-by-step explanation:

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2 years ago

FIRST TO ANSWER WILL BE MARKED BRAILIEST! WORTH 20 POINTS!

pshichka [43]

Answer:

The score on the next test must be between 86 and 98, inclusive

Step-by-step explanation:

Write an inequality using the average:

86 ≤ $\frac{83+89+x}{3}$ ≤ 90

Solve for x:

multiply everything by 3:

258 ≤ x + 83 + 89 ≤ 270

258 ≤ x + 172 ≤ 270

subtract 172 from everything:

86 ≤ x ≤ 98

The score on the next test must be between 86 and 98, inclusive

7 0

3 years ago

Select all the expressions with a product greater to 2/3

Naddika [18.5K]

Answer:

3.LOOK AND CHOOSE THE CORRECT SENTENCES

(1 Punto)

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Step-by-step explanation:

6 0

3 years ago