Answer:
The calculated value t = 3.050 < 3.8325 at 0.0025 level of significance
The null hypothesis is accepted
The sample data support the claim that shelf life has increased.
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the Mean of the Population = 216days
Given that sample size n=9
Given that mean of sample x⁻ = 217.222 days
Given that the Standard deviation of the sample (S) = 1.2019days
<em><u>Step(ii):-</u></em>
<em><u>Null hypothesis:-H₀:</u></em>The sample data support the claim that shelf life has increased.
Alternative Hypothesis:H₁: The sample data support the claim that shelf life has decreased
Test statistic


t = 3.050
Degrees of freedom γ = n-1 = 9-1 =8
t₀.₀₂₅ = 3.8325
<em><u>Final answer:-</u></em>
The calculated value t = 3.050 < 3.8325 at 0.0025 level of significance
The null hypothesis is accepted
The sample data support the claim that shelf life has increased.