In my opinion if I calculated correctly it should be 35 35 19 19
Answer:
3.14 (π)
√-1
0.6
Step-by-step explanation:
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If you consider the logarithm base 3 of both sides, you have

You can use a rule of logarithms that allow you to turn exponents into multiplicative factors:

So the equation becomes

Now, by definition, you have

So, you have

So, the equation becomes

Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />