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Iteru [2.4K]
3 years ago
11

I need help with this...

Mathematics
1 answer:
solniwko [45]3 years ago
4 0
This can be represented as the equation
x/48 + 1/3 = 47/48

In order to solve this we need to siolate x ( get x in one side of the equation by itself and the rest in the other)

We can do that by subtracting 1/3 from both sides of the equation, by doing this we eliminate 1/3 from the left side of the equation and since we did it on both sides of the equations, it still is an equation ( one side equals the other )

x/48 + 1/3 - 1/3 = 47/48 - 1/3
1/3 - 1/3 cancel out, so we get
x/48 = 47/48 - 1/3
To subtract 47/48 - 1/3 ( and all other equations), the denominator of all fractions need to be the same. We can make the denominators equal by setting 1/3 as 16/48, which is the same thing as 1/3.

x/48 = 47/48 - 16/48
x/48 = 31/48

Now to fully isolate x, we can just multiply both sides by 48, so the x/48 turns into 48/48x or just x, and the 31/48 just turns into 31.
x = 31 x 48/48
x = 31

so 31/48 + 1/3 = 47/48
This was quite long but I hope it helps if you didnt understand how to solve equations
:)
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lisov135 [29]

Answer: Part A is 2 and 6 Part B is 2

Step-by-step explanation:

Part A: Here is the explanation. So, you started at with the expression 3x^2+8x+4 and when you're are factoring, you have 3x^2+px+pq+4. You can substitute the p and q for 6 and 2. What they did is they replaced 8x with px+qx. To get 8x, p needs to be 6 and q needs to be 2, or the other way around. TIP: The numbers just have to add up to 8 on this one. It doesn't have to be 6 and 2.

Part B: Here is what I got so far... 3x(x+r) is 3x^2+3xr. Also, s(x+r) is sx+sr. The equation becomes, 3x^2+3xr+sx+sr. R can be 2 and s can be 2. Here is my reasoning: The original expression was 3x^2+8x+4. We already have the 3x^2, so now we need to find what the others are by determining what r and s equal. R and s can both be 2 to make four. 2x2 is 4. Let's see if it can make 8.  3xr becomes 6x and sx becomes 2x. 6x+2x is 8x.

4 0
3 years ago
Pls explain how you figured out both questions
Mariana [72]

Answer:

A=0.125

B=0.125

Step-by-step explanation

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6 0
3 years ago
What is the coefficient of the x^4 term in the expanded form of (2x-7)^6
Artist 52 [7]

Answer:

The coefficient of x^{4} = 11760

Step-by-step explanation:

∵ The rule of expanded the binomial is :

(a+b)^{n}=C_{0} ^{n} a^{n}b^{0}+C_{1}^{n}a^{n-1}b^{1}+C_{2}^{n}a^{n-2}b^{2}+.............

∴ The Expanded of (2x-7)^{6} is:

(2x-7)^{6}=C_{0}^{6}(2x)^{6}(-7)^{0}+C_{1}^{6}(2x)^{5}(-7)^{1}+C_{2}^{6}(2x)^{4}(-7)^{2}+..........

(2x-7)^{6}=(1)(64x^{6})(1)+(6)(32x^{5})(-7)+(15)(16x^{4})(-7)^{2}

We will take the term of x^{4} and find the coefficient of it

∴ The coefficient of x^{4} = (15)(16)(-7)^{2}=(15)(16)(49)=11760

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3 years ago
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aleksklad [387]
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Step-by-step explanation:

6 0
3 years ago
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