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3 years ago

13

Can someone please help me with this?

2 answers:

alex41 [277]3 years ago

7 0

I think it is A but I am not 100 percent sure.

maksim [4K]3 years ago

3 0

884,250+459,810= 1,344,060

BRAINLIEST PLEASE

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If sec theta = - √30 / 3, find cos theta.<br> if sin(-theta) = -0.97, find cos (π/2 - theta).

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Step-by-step explanation:

$\cos \theta = \frac{1}{ \sec\theta } = - \frac{3}{ \sqrt{30} } = - \frac{3 \sqrt{30} }{30} = - \frac{ \sqrt{30} }{10}$

$\cos( \frac{\pi}{2} - \theta )= \cos \frac{\pi}{2} \cos \theta + \sin \frac{\pi}{2} \sin \theta$

Note that

$\sin( - \theta) = - \sin \theta$

$\cos \frac{\pi}{2} = 0 \: \: \: \: \: \sin \frac{\pi}{2} = 1$

Therefore,

$\cos( \frac{\pi}{2} - \theta ) = 0.97$

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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A university's freshman class has 5000 students. 50% of those students are majoring in Computer Science. How many students in th

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3 years ago

The researcher has limited resources. He sends 9 emails from a Latino name, and 14 emails from a non-Latino name. For the Latino

deff fn [24]

Answer: 38.41 minutes

Step-by-step explanation:

The standard error for the difference in means is given by :-

$SE.=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2}}$

where , $\sigma_1$ = Standard deviation for sample 1.

$n_1$ = Size of sample 1.

$\sigma_2$ = Standard deviation for sample 2.

$n_2$ = Size of sample 2.

Let the sample of Latino name is first and non -Latino is second.

As per given , we have

$\sigma_1=82$

$n_1=9$

$\sigma_2=101$

$n_2=14$

The standard error for the difference in means will be :

$SE.=\sqrt{\dfrac{(82)^2}{9}+\dfrac{(101)^2}{14}}$

$SE.=\sqrt{\dfrac{6724}{9}+\dfrac{10201}{14}}$

$SE.=\sqrt{747.111111111+728.642857143}$

$SE.=\sqrt{1475.75396825}=38.4155433158\approx38.41$

Hence, the standard error for the difference in means =38.41 minutes

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3 years ago