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3 years ago

What is the answer to the following equation 13pt13-p

Mathematics

1 answer:

xeze [42]3 years ago

8 0

You have to distribute it.
EXPLANATION:

13 pt 13-p
13-13
0 pt-p
-p-0
-p= 14
14 pt
= 14

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Raju bought seven notebooks of two hundred pages and five of hundred pages, for 107 rupees. Joseph bought five notebooks of two

olga nikolaevna [1]

Answer:

Large books = 11

Small books = 6

Step-by-step explanation:

7x + 5y = 107

7x = 107 - 5y

x = 107/7 - 5y/7

5x + 7y = 97

5 (107/7 - 5y/7) + 7y = 97

535/7 - 25y/7 + 7y = 97

535/7 + 24y/7 = 97

535 + 24y = 679

24y = 679 - 535

y = 144/24 = 6: So x =

7x + 5(6) = 107

7x = 107-30

x = 77-7 = 11

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3 years ago

20 POINTS! Please help, best answer will recessive brainliest answer points as well as 5 stars and a thank you. :)

Vitek1552 [10]

Answer:

3): 14

Step-by-step explanation:

The problem states that ABC and DEF are similar. Therefore, dsue to similar triangles, we have 7x/7=4/x, so x^2=4. Therefore, x=2 (because x cannot be negative). Therefore, AB = 7x = 7*2=14

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2 years ago

Based on the information provided in the net worth statement , what was the net worth of this person for 12/31/2012?

Paraphin [41]

The correct answer for this is D

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3 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

2 years ago

Im confuesd with this question so can you please help thanks!

stepladder [879]

Answer:

It's asking you to pick the answer that is closest to the circumference. But before you just pick any answer you need to find the circumference of the circle.

Step-by-step explanation:

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2 years ago

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