Answer:
E I think
Explanation:
Turning glucose into pyruvates (Glucose got split)
Is there options that I can shoes from
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
Answer:
7 cat and lion
8. animalia chordata and mammalia
9 mammalia
10 chordata
11 <em>Felis domesticus</em>
<em>Felis concolor</em>
<em>Canis familiaris</em>
<em>Hom0 sapiens</em>
<em>have to change the o to a 0 to get them to accept the answer</em>
Explanation:
