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dlinn [17]
2 years ago
14

An equation of a line through (-1, 4) which is perpendicular to the line y = 4x + 1 has slope and y-intercept

Mathematics
1 answer:
Assoli18 [71]2 years ago
7 0

Answer:

The answer to your question is   y = -1/4x + 15/4

Step-by-step explanation:

Data

P (-1, 4)

⊥ y = 4x + 1

Process

1.- Find the slope of the line given

       y = 4x + 1

slope = 4

2.- Find the slope of the new line

     slope 2 = -1/4

3.- Find the equation of the line

       y - y1 = m(x - x1)

Substitution

       y - 4 = -1/4(x + 1)

Simplification

       y - 4 = -1/4x - 1/4

       y = -1/4x - 1/4 + 4

       y = -1/4x - 1/4 + 16/4

Result

       y = -1/4x + 15/4

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X and y intercepts of y=3x-6
Slav-nsk [51]

Answer:

x intercept=2, y intercept= -6

Step-by-step explanation:

X Intercept is when the graph crosses the X Axis, point of intersection. To find it, just convert into standard form and solve for x by getting rid of y.

The Y-intercept is where the line crosses the y-axis, point of intersection. It is the constant in the slope-intercept form.

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3 years ago
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Kruka [31]

Answer:

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Step-by-step explanation:

10 is the number that has the most number of dots above it.

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3 years ago
Kathleen, Penny, and Megan all order 12-ounce smoothies. After 5 minutes, Kathleen still has 3/4 left, Penny has 5/6 left, and M
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you have to find the common denominator(number that all of the denominators are divisible into.
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Llana [10]

Answer:

Im not sure but lets play warzone

Step-by-step explanation:

4 0
3 years ago
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Slav-nsk [51]

Answer:

Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.  

Step-by-step explanation:

Given:

Let,

point S( x₁ , y₁) ≡ ( -1 , 1)  

point T( x₂ , y₂) ≡ (3 , -5)

Point M( x , y ) is the Mid point of segment ST.  

To Find:

Point M( x , y )= ?

Solution:

As Point M( x , y ) is the Mid point of segment ST.

So we have Mid Point Formula as

Mid\ pointM(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

On substituting the given values in above equation we get

M(x,y)=(\frac {-1+3}{2},\frac{-5+1}{2})\\\\M(x,y)=(\frac{2}{2},\frac{-4}{2}) \\\\M(x,y)=(1,-2)\ \textrm{which the required midpoint}

Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.  

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