Answer:
-26 × -1 = 26
This is your answer , pls mark me the brainliest!!
Let X be the first number
there is a 2 numbers distance between each even number eg.2 ,4, 6, 8, etc.
So the 2nd number is X+2
The sum of the 1st and 2nd numbers = 14
X + X+2 =14
2X +2 =14
2X = 14-2
2X = 12
X = 12/2
X = 6
Therefore,
The first number i.e, X = 6
And the second number i.e, X+2 = 6+2 =8
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This is the only positive pair in case of two consecutive numbers if the are even numbers but not consecutive there will be more pairs
12 + 2 = 14
10 + 4 = 14
8 + 6 = 14 (Already found)
Answer:
30,240 ways
Step-by-step explanation:
This question is bothered on permutation. Permutation has to do with arrangement.
If there are 10 computers and 5 students, the number of ways students will sit at the computers if no computer has more than one student can be expressed as;
10P5 = 10!/(10-5)!
10P5 = 10!/(5)!
10P5 = 10*9*8*7*6*5!/5!
10P5 = 10*9*8*7*6
10P5 = 30,240
Hence the number of ways is 30,240 ways
Answer:
c. quadrilateral
Step-by-step explanation:
All of the sides are different lengths, so the quadrilateral cannot be a parallelogram, rhombus, or square.
Its best descriptor is <em>parallelogram</em>.
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A <em>parallelogram</em> has opposite sides parallel and congruent. A <em>rhombus</em> also has adjacent sides congruent. A <em>square</em> is a special case of rhombus in which the corner angles are right angles.
