So you want to get all of the unknowns on one side and all the kknowns on the other (this only works with one placeholder)
with equation you must do the same thing to both sides (except divide by 0 which is not allowed and undifined) so that the equation stays equall so
14y-51=187+4y
so add 51 to both sides
14y=238+4y
subtract 4y from both sides
10y=238
divide both sides by 10
y=23.8
(y=17 would make the equation false)
answer is y=23.8
677 mi^2
find the area of the two triangles and double them(or just not divide by two on both of them since they’re being doubled anyways) and then add the area of the bottom rectangle.
Using PEMDAS or order of operations: 2*0 is 0 and 10-0 is 10 and then 3/10 is 3/10 plus 12 is 12 3/10
Answer:
1(7x-19y)
Step-by-step explanation:
these are both prime numbers so the gcf is 1
hopes this helps please mark brainliest
Answer:
The rate of change of the surface area of the sphere is 0.99 cm²/s.
Step-by-step explanation:
The surface area (A) of a sphere is given by:
If we derivate the above equation with respect to the time we have:
(1)
Where:
r: is the radius
We need to find 
and r.
From the volume we can find the radius:
![r = \sqrt[3]{\frac{3V}{4\pi}} = \sqrt[3]{\frac{3*256*\frac{\pi}{3}}{4\pi}} = 4 cm](https://tex.z-dn.net/?f=%20r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B3%2A256%2A%5Cfrac%7B%5Cpi%7D%7B3%7D%7D%7B4%5Cpi%7D%7D%20%3D%204%20cm%20)
And by derivating the volume of the sphere with respect to the time we can calculate :
Now, we can calculate the rate of change of the surface area (equation 1):
Therefore, the rate of change of the surface area of the sphere is 0.99 cm²/s.
I hope it helps you!
