We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
The balance was $4400.25 before 4 years.
<h3>What is an Equation?</h3>
An equation is a mathematical statement formed when two expressions are equated using an equal sign.
The equations are useful in the determination of unknown parameters.
The equations are of various types, such as Trigonometric equations, and quadratic equations.
The balance of an investment account is $308.32
Let the balance 4 years ago was $x
Then the balance today is represented by x + 308.32
The current balance is $4708.57
The expressions can be equated to get the value of the balance 4 years ago.
x + 308.32 = 4708.57
x = 4708.57 - 308.32
x = $4400.25
The balance 4 years ago was $4400.25
To know more about Equation
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Answer:
there is no pic
Step-by-step explanation:
Answer:
its 0.25 or 2 one of those
Step-by-step explanation:
most likely 0.25 but
