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Nana76 [90]
3 years ago
5

Annette wanted to buy new carpet for her L-shaped room.

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
4 0
The best answer to your problem would most likely be A because it makes the most sense. Hope I helped.

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The Statue of Liberty is approximately 300 ft. tall, and the right arm is approximately 42 ft. long. On a scale model that is 2
Archy [21]

Answer:

Weight of copper: 62,000 lbs. (31 tons). Weight of framework: 250,000 lbs. (125 tons). Weight of concrete foundation: 54,000,000 lbs. Thickness of copper sheeting: 3/32 of an inch, the thickness of two pennies placed together.  the answer in 125

Step-by-step explanation:

4 0
2 years ago
7 is a factor of which number?<br> 28<br> 16<br> 11<br> 4 4
maw [93]

Answer:

28

Step-by-step explanation:

28 = 7 x 4

So,

7 is a factor of 28.

6 0
3 years ago
A right triangle has three sides with length 148, 140, and 48. What is the length of the hypotenuse?
Oksanka [162]
145 i think im only three

5 0
3 years ago
Help me pleaseeeee!!!
arlik [135]

Answer:

(6, 5) is the answer.

Step-by-step explanation:

The y's intersect at (6, 5)

3 0
3 years ago
A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 5 large boxes and 3 small boxes has a t
faltersainse [42]

Answer:

one large box equals 15.75<em>kg</em>

one small box equals 13.75<em>kg</em>

Step-by-step explanation:

First, identify your variables:

Let "l" represent the weight of one large box.

Let"s" represent the weight of one small box.

Then, stack the two equations on top of each other:

5l+3s=120\\7l+9s=234

Next, multiply the first equation by 3 so we can use elimination of the "s" variable to find the "l" variable first:

3(5l+3s=120)\\7l+9s=234\\\\15l+9s=360\\7l+9s=234

Now, subtract the two equations to cancel out the s-variable and find the l-variable:

15l+9s=360\\-(7l+9s=234)\\8l=126\\\frac{8l}{8}=\frac{126}{8}\\l=15.75

Then, substitute your l-variable in the original first equation to find the s-variable:

5l+3s=120\\5(15.75)+3s=120\\78.75+3s=120\\78.85-78.75+3s=120-78.75\\3s=41.25\\\frac{3s}{3}=\frac{41.25}{3}\\s=13.75

With all the information that is collected, you find that one large box weighs 15.75<em>kg</em> and one small box weighs 13.75<em>kg</em>.

4 0
3 years ago
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