Answer:
a = -3/2
Step-by-step explanation:
3(6a+12)=9
Divide each side by 3
3/3(6a+12)=9/3
6a+12 = 3
Subtract 12 from each side
6a+12-12 = 3-12
6a = -9
Divide by 6
6a/6 = -9/6
a = -3/2
15 - 9 + 2.65 + 1.35 + 3.48
6 + 2.65 + 1.35 + 3.48
8.65 + 1.35 + 3.48
10 + 3.48
13.48
Isolate the variable by dividing each side by factors that don't contain the variable.
x = 1
-6+3x+4=2-4x+3
-8+7x+1=0
7x=7
x=1
Answer:
The distance A’C’ is 4.47 units
Step-by-step explanation:
Before we go on, we need to get the appropriate transformation
Mathematically, we have a 90 degrees clockwise rotation yielding the following;
(x,y) to (-y,x)
A is (-4,1)
C is (-2,5)
By transforming, we have
A’( -1,-4)
C’ (-5,-2)
To get the magnitude of the line segment, we are going to use the distance formula between points
We have this as;
D = √(x2-x1)^2 + (y2-y1)^2
D = √(-5-(-1))^2 + (-2-(-4))^2
D = √(-4)^2 + (2)^2
D = √(16 + 4)
D = √20
D = 4.47 units
