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3 years ago

If 16-7w=w+14-6, what is the value of w-1?

Mathematics

1 answer:

svet-max [94.6K]3 years ago

7 0

value of w-1 ⇒ 1-1 = 0 .

Step-by-step explanation:

We have , 16-7w=w+14-6 . We need to find value of w-1 . Let's find out:

⇒ $16-7w=w+14-6$

⇒ $(16-7w)-16=(w+14-6)-16$

⇒ $-7w=w-8$

⇒ $(-7w)+8=(w-8)+8$

⇒ $(-7w)+8=w$

⇒ $(-7w+8)+7w=w+7w$

⇒ $8=8w$

⇒ $\frac{8}{8}=\frac{8w}{8}$

⇒ $w=1$

So , value of w-1 ⇒ 1-1 = 0 .

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I need help with Function Operations

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Answer:

490

Step-by-step explanation:

d(x)=700-7(30)

7x 30=210

700-210=490

therefore,

r(x)=490

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2 years ago

Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
║
Neither
⊥
║
Neither
Neither
Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are neither parallel or perpendicular

Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are parallel

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are Neither parallel nor perpendicular

Neither

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are perpendicular

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are parallel

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = $\dfrac{13}{5}$

Therefore, the two equations are neither parallel nor perpendicular

Neither

7. The equations are;

2·x + 6·y = -3

Which gives $y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}$

12·y = 4·x + 20

Which gives

$y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}$

m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

Neither

8. 2·x - 5·y = -3

Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

5·x + 27 = 6

$x = -\dfrac{21}{5}$

Therefore, the slopes are not equal, or perpendicular, the correct option is Neither

Learn more here:

brainly.com/question/16732089

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3 years ago

Jerry purchased three pens for $1.19 each and six notebooks for $2.29 each. How many did Jerry spend altogether?

Masteriza [31]

Hi!

We will find the sum you are looking for like this:

3 * 1,19$ + 6 * 2,29$ = 3,57$ + 13,74$ = 17,31$.

Hope this helps!

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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