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mr_godi [17]
3 years ago
13

An airplane is preparing to land at an airport. It is 51,300 feet above the ground and is descending at the rate of 3,000 feet p

er minute. At the same airport, another airplane is taking off and will ascend at the rate of 2,700 feet per minute. When will the two airplanes be at the same altitude and what will that altitude be ?
Mathematics
1 answer:
Xelga [282]3 years ago
8 0

I whom answer it tomorrow I am busy :p

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(NEED ASAP) 15 POINTS
yulyashka [42]

Answer:

1 and 2 go in the 2nd area and 3 gos to the 1st and 4th gos to the last one

Step-by-step explanation:

hope this helped!

P.S. can i pls have brainlyist am trying to lv up thx! ;D

6 0
3 years ago
Imagine you have some workers and some handheld computers that you can use to take inventory at a warehouse. There are diminishi
Svet_ta [14]

Answer:

a. $1.03

b. $0.93

c. 0.98

d. 2 workers

Step-by-step explanation:

a. Given that:

  • 1 computer : 1 worker : inventory 150 items per hour
  • 1 computer : 2 workers : inventory 200 items per hour
  • 1 computer : 3 workers : inventory 220 items per hour
  • 1 computer : 4+ workers : fewer than 235 items per hour
  • Cost: $100 per computer ; $25 per worker

The fixed production factor in the warehouse is the computer used:

-One computer used, but the number of users is varied to inventory a specified number of items.

-The variable production factor is the number of workers assigned per one computer.

#The cost of inventorying a single item by one worker is:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_1=\frac{125+30}{150}\\\\\\=1.03

Hence, the cost of inventorying a single item is $1.03

b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_2=\frac{125+2\times30}{200}\\\\\\=0.925

Hence, the cost of inventorying a single item is $0.93

c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_3=\frac{125+3\times30}{220}\\\\\\=0.98

Hence, the cost of inventorying a single item is $0.98

d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.

Take any number less than 235(say 234) as the inventory units:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_4=\frac{125+4\times30}{234}\\\\\\=1.05

From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.

4 0
3 years ago
Will give brainliest i rlly need help
Zepler [3.9K]

Answer:

1/6

Step-by-step explanation:

-3/4 - (-1/2) = - 1/4

-2/3 - 5/6 = - 3/2

-1/4 ÷ -3/2

3 0
2 years ago
Sorry I need help with these 3! Thank you to whoever takes the time to solve them!!!
mash [69]
1.)
Starts with 40:10, then cuz you have 80 buns, you need to x2, so it would be 20 cubes

2.)
I don’t know, sorry

3.)
4:2 and 60 in total
so 4+2 is 6 and 60/6 is 10
so it would be 40:20 so 20

hope this helps :)
8 0
3 years ago
HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
goldfiish [28.3K]
Setup is
y = k/x
8 = k/3
k = 24

Now use 6 for y
6 = 24/x
x = 24/6 = 4 or A
5 0
3 years ago
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