A basketball coach will select the members of a five-player team from among 9 players, including John and Peter. If the five pla
1 answer:
Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter==35
Total no of ways = =126
= =
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Answer:
A
Step-by-step explanation:
It's hard to see but when x is 6, y is 4.5. Just plug that into each equation and see which one is correct.
The first thing we must do for this case is to define variables.
We have then:
x: number of slices
y: total cost
We write the linear function that relates the variables.
We have then:
Then, we evaluate the number of slices to find the total cost.
-two slices cost:
We substitute x = 2 in the given equation:
Answer:
two slices = 2.2 $
-ten slices cost:
We substitute x = 10 in the given equation:
Answer:
ten slices = 11 $
-half a slice cost:
We substitute x = 1/2 in the given equation:
Answer:
half a slice = 0.55 $