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2 years ago

What is the exponential form of 175

Mathematics

1 answer:

Serggg [28]2 years ago

5 0

First factor 175:

1, 5, 5, 7

Now that we know the factors of 175, combine common factors:

1, 5², 7

Hope this helps!

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A+5=6 a . a = 0 b. a = 1 c. a = 2

Nastasia [14]

A+5=6
Subtract 5 from both sides
A+5-5=6-5
A=1

Hope that helps

4 0

2 years ago

Read 2 more answers

Number 6 part a & b Number 7 Please & thank you

miv72 [106K]

Answer:

6- Part A: $750a+1200r=1000000$

Part B: $1065a+876r=1000000$

Solution of the system: $a\approx521.739\;\;\;\;b\approx507.246$

Step-by-step explanation:

Part A:

In words, the equation is formed like this:

Total kg of Arabica + Total kg of Robusta = Total kg of coffee

Now, the total of each yield is calculated by the product of kg/hectare and number of hectares. Thus, the equation is:

$750a+1200r=1000000$

Part B:

In words:

Arabica's worth + Robusta's worth = plantation worth

Each yield's worth is given by the product of the price per kg and the corresponding production. So, the equation is:

$1.42(750a)+0.73(1200r)=1000000\\1065a+876r=1000000$

3 0

2 years ago

Evaluate the following expression 1/3^2

NISA [10]

Answer:

1/9

Step-by-step explanation:

1/3*1/3=1/9

6 0

3 years ago

ANSWER THIS BEFORE 3 MINUTES, AND I WILL GIVE YOU BRAINIEST AND 15 POINTS!!!

Zina [86]

1888888888888888888777754%&-76$$

8 0

3 years ago

The brand manager for a brand of toothpaste must plan a campaign designed to increase brand recognition. He wants to first deter

VMariaS [17]

Answer:

He must survey 123 adults.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

Assume that a recent survey suggests that about 87% of adults have heard of the brand.

This means that $\pi = 0.87$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

How many adults must he survey in order to be 90% confident that his estimate is within five percentage points of the true population percentage?

This is n for which M = 0.05. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.05 = 1.645\sqrt{\frac{0.87*0.13}{n}}$

$0.05\sqrt{n} = 1.645\sqrt{0.87*0.13}$

$\sqrt{n} = \frac{1.645\sqrt{0.87*0.13}}{0.05}$

$(\sqrt{n})^2 = (\frac{1.645\sqrt{0.87*0.13}}{0.05})^2$

$n = 122.4$

Rounding up:

He must survey 123 adults.

6 0

2 years ago