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Elena-2011 [213]

4 years ago

5

Write an expression using fractions to show how to determine the amount that each person will pay. Then calculate each person's

contributions showing all steps in long division. There are 4 people and the total amount is $42.78

2 answers:

Ne4ueva [31]4 years ago

5 0

The correct answer is 7

Viefleur [7K]4 years ago

3 0

Answer:

4÷42.78=10.69

Step-by-step explanation:

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Please help I don't get this question

ahrayia [7]

The first one: 10x+30

6 0

3 years ago

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In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any

Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

$E \cap F = \emptyset,\quad E \cup F = \Omega$

where $\Omega$ is the whole sample space.

This implies that

$P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)$

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day $d_1$ .

The second footballer can be born on any other day, so he has 364 possible birthdays:

$d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}$

the probability for the first two footballers to be born on two different days is thus

$1 \cdot \dfrac{364}{365} = \dfrac{364}{365}$

Similarly, the third footballer can be born on any day, except $d_1$ and $d_2$ :

$d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}$

so, the probability for the first three footballers to be born on three different days is

$1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}$

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

$\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

So, the probability that at least two footballers are born on the same day is

$1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

since the two events are complementary.

8 0

3 years ago

Which of the following has no solution?

xz_007 [3.2K]

<span>{x | x < 0} and {x | x > 0}</span>

8 0

3 years ago

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What is the condition of loss ?1)sp>mp 2)CP>sp 3) sp>CP 4)mp>sp

victus00 [196]

Step-by-step explanation:

what is the condition of loss ?1)sp>mp 2)CP>sp 3) sp>CP 4)mp>sp

3 0

3 years ago

the tortoise can walk 1/2 mile in 1/4 of an hour. The hare can run 11/2 mile in half an hour. What is the distance

Shalnov [3]

Answer:

The speed of tortoise is 2 miles per hour and

The speed of hare is 11 miles per hour

Step-by-step explanation:

Given as :

The distance cover by tortoise = $\frac{1}{2}$ miles

The Time taken by tortoise to cover distance = $\frac{1}{4}$ hour

So, The speed of the tortoise is = $\dfrac{\textrm Disatnce cover by tortoise}{\textrm time taken}$

I.e The speed of the tortoise = $\frac{\frac{1}{2}}{\frac{1}{4}}$

∴ The speed of the tortoise = 2 miles per hour

Again ,

The distance cover by hare = $\frac{11}{2}$ miles

The Time taken by hare to cover distance = $\frac{1}{2}$ hour

So, The speed of the hare = $\dfrac{\textrm Disatnce cover by hare}{\textrm time taken}$

I.e The speed of the hare = $\frac{\frac{11}{2}}{\frac{1}{2}}$

∴ The speed of the hare = 11 miles per hour

Hence The speed of tortoise is 2 miles per hour and

The speed of hare is 11 miles per hour . Answer

5 0

4 years ago