Answer:
it would be 81 because you multiply 3 times 3 ties 3 times 3 equals 81
The answer would be $280.00.
The answer is B) f(x) is an even function for all even values of <em>m.</em>
Answer:
a) 1 cupcake = $5.50
b) 1 Popsicle = $3.50
Step-by-step explanation:
Let s = cost of one soda
Let c = cost of one cupcake
Let p = cost of one Popsicle
From the given information we can create 3 equations:
- Equation 1: s + c + p = 22
- Equation 2: s + 3c + 3p = 40
- Equation 3: c = p + 2
Subtract Equation 1 from Equation 2 to eliminate the variable s:
s + 3c + 3p = 40
<u>- s + c + p = 22</u>
<u> 2c + 2p = 18</u>
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Substitute Equation 3 into this new equation and solve for p:
⇒ 2c + 2p = 18
⇒ 2(p + 2) + 2p = 18
⇒ 2p + 4 + 2p = 18
⇒ 4p = 14
⇒ p = 3.5
Substitute the found value of p into Equation 3 and solve for c:
⇒ c = p + 2
⇒ c = 3.5 + 2
⇒ c = 5.5
To find the cost of a soda (s), substitute the found values of p and c into Equation 1:
⇒ s + c + p = 22
⇒ s + 5.5 + 3.5 = 22
⇒ s = 13
Therefore,
- 1 soda costs $13
- 1 cupcake costs $5.50
- 1 Popsicle costs $3.50
Star with the statement: "Given that the sum is 11"
which may seem a bit odd considering its the last part of the problem
The "given" is important as it sets up the constraints of what we're dealing with. In this case, we know 100% (we can see or someone told us without lying) that the sum is 11. We don't know what the individual values are but we know they add to 11.
What are the ways to add to 11? Well they are...
5+6 = 11
6+5 = 11
so there are 2 ways to do it. As you can see, none of those ways involve a double. A double is where we have two of the same values (eg: snake eyes which is 1 and 1 giving 1+1 = 2 as the sum). It turns out that it's impossible to have doubles add to any odd number.
So if we know the sum is 11, and we're asking "what is the probability of rolling doubles", then the answer is 0.
The 0 indicates "impossible" or "certainty of it never happening".
