We have
<span>Va(airplane)=150
East</span>
Vw(wind)=7.1
South East
<span>
</span><span>resulting vector R</span>
airplane
Vax=150 Vay=0 it only has component x
WindVwx=7.1*cos45=5.02
Vwy=7.1*sin45=-5.02
is negative because is South direction
|R|=(Rx^2+Ry^2) ^0.5
Rx=150+5.02=155.02
Ry=0-5.02=-5.02
<span>|R|=155.10
miles/hour South East</span>
Determine angle θ
Rx=R*cos(θ)
<span>Cos(θ)=Rx/R</span>
<span>Cos(θ)=155.02/155.10=0.9995</span>
θ =arc cos Rx/R
θ =1.8119 º
Rx represents the component in the East direction of the resultant force. Your contribution is given by both, the force of the plane and the wind. The contribution of the wind makes the airplane's speed greater
Ry represents the component in the South direction of the resulting force
Its contribution is exclusive of the wind since the airplane has no component
in this direction
|R| the force resulting from the combined action of the force of the plane and the force of the wind
θ represents the angle that forms the resultant force with respect to the x axis or east direction
Answer:
5:2
Step-by-step explanation:
35÷7= 5
14÷7=2
You get the ratio by dividing by a common multiple
Answer:
They are 24, 692 feet aprart
Step-by-step explanation:
Let us assume at the instance we are measuring their position, that Pluto is at the highest point in the air, which is = 24,568 feet, and Goofy is at the lowest point of the sea (that he can go) = 124 feet.
Before we can proceed with the addition, we need to establish a datum, which will serve as the reference point from which the two distances are measured. This definitely is the sea level, because altitude and depth are usually measured above and below sea level.
Pluto's location to the sea level = 24,568 feet
Goofy's Location to the sea level = 124 feet
their distance apart = 24,568 feet + 124 feet =24, 692 feet apart
