The wholesale price of a TV is 65 % less than retail price. Therefore, the wholesale price is _____ times the retail price.
2 answers:
Answer:
The wholesale price is <u>0.35</u> times the retail price.
Step-by-step explanation:
We have been given that the wholesale price of a TV is 65% less than retail price.
The whole sale price would be 35% of the retail price as .
Let us convert 35% as a decimal.
Therefore, the wholesale price is <u>0.35</u> times the retail price.
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Correct Answer:
C option: 6 feet
Solution:
Since <span>Yolanda wants to keep the pool in proportion to the model, the ratio of diameter to depth of model and the pool will be same.
Let the depth of pool is x feet. So we can write:
Ratio of Diameter to Depth of Model = Ratio of Diameter to Depth of pool
</span>
<span>
This means the depth of pool should be 6 feet if </span><span>Yolanda wants to keep the pool in proportion to the model.</span>
C option: 6 feet
Solution:
Since <span>Yolanda wants to keep the pool in proportion to the model, the ratio of diameter to depth of model and the pool will be same.
Let the depth of pool is x feet. So we can write:
Ratio of Diameter to Depth of Model = Ratio of Diameter to Depth of pool
</span>
<span>
This means the depth of pool should be 6 feet if </span><span>Yolanda wants to keep the pool in proportion to the model.</span>
A) Since a is last in line, we can disregard a, and concentrate on the remaining letters.
Let's start by drawing out a representation:
_ _ _ _ a
Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways
b) Since a is before d, we need to account for all of the possible cases.
Case 1: a d _ _ _
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d
Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.
a b c _ _
We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:
_ a b c _
_ _ a b c
So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.
In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).
Let's start by drawing out a representation:
_ _ _ _ a
Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways
b) Since a is before d, we need to account for all of the possible cases.
Case 1: a d _ _ _
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d
Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.
a b c _ _
We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:
_ a b c _
_ _ a b c
So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.
In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).