10) PLS HELP ASAP!!! 10 + POINTS AND BRAINLIEST
2 answers:
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Answer:
Option B. house B; monthly payment of $1,550.89 is the correct answer.
Step-by-step explanation:
In order to calculate the highest payment Pete can afford we have to subtract his expenses from his housing budget.
Given
Total housing budget = $2250
Monthly costs = $215.75
Utilities = $143.50
Taxes = $273
First all expenses can be added together to subtract from the housing budget.
So
Now the total monthly cost will be subtracted from housing budget.
Hence, he saves $1617.75 for monthly payment.
Looking at the options, C and D will be ruled out as both the quantities are greater than 1617.75
Option A and B both are smaller than 1617.75 but as $1,550.89>$1,327.18, Option B is the highest monthly payment Pete can afford.
Hence,
Option B. house B; monthly payment of $1,550.89 is the correct answer.
Answer:
We estimate to have 8.33 times the number 6 in 50 trials.
Step-by-step explanation:
Let us consider a success to get a 6. In this case, note that the probability of having a 6 in one spin is 1/6. We can consider the number of 6's in 50 spins to be a binomial random variable. Then, let X to be the number of trials we get a 6 out of 50 trials. Then, we have the following model.
We will estimate the number of times that she spins a 6 as the expected value of this random variable.
Recall that if we have X as a binomial random variable of n trials with a probability of success of p, then it's expected value is np.
Then , in this case, with n=50 and p=1/6 we expect to have number of times of having a 6, which is 8.33.
Answer:
Each Tomskian build 6 igloos per week.
Each Kyzylian build 5 igloos per week.
Step-by-step explanation:
Let T represent the number of Tomskians and K represent the number of Kyzylians the company needs to employ to meet its goal.
The inequality: represents the situation that a company plans to build at least 152 igloos in a single week by employing T Tomskians and K Kyzylians.
We can see that 6T represents the number of igloos made by T Tomskians in one week and 5K represents the number of igloos made by K Kyzylians in one week .
Since all Tomskians and Kyzylians build the same number of igloos per week, therefore, each Tomskian build 6 igloos per week and each Kyzylian build 5 igloos per week.