Given: Alonzo's suitcase can weigh no more than 20 kilograms if he wants to take it on the airplane without paying a fee.
Let x denote the weight of suitcase, then
We know that 1 kg =10 hg
Therefore, 20kg=
⇒
Since, the weight of his suitcase is 220 hg.
The amount of weight will Alanzo have to take out of his suitcase to meet the weight limit will be :-
Hence, 20 hg of weight have to take out of his suitcase to meet the weight limit.
Answer:78.396 pounds
Step-by-step explanation:
32 students in 1 row
16 students in 2 rows
8 students in 4 rows
4 students in 8 rows
2 students in 16 rows
The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
