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Katena32 [7]
3 years ago
13

What value of x makes the following equation true? 15+3x=3(2−2x)

Mathematics
1 answer:
Alinara [238K]3 years ago
5 0

Answer:

\boxed {x = -1}

Step-by-step explanation:

Solve for the value of x:

15 + 3x = 3(2 - 2x)

-Use <u>Distributive Property</u>:

15 + 3x = 3(2 - 2x)

15 + 3x = 6 - 6x

-Take 6x and add it to 3x:

15 + 3x + 6x = 6 + 6x - 6x

15 + 9x = 6

-Subtract both sides by 15:

15 - 15 + 9x = 6 - 15

9x = -9

-Divide both sides by 9:

\frac{9x}{9} = \frac{-9}{9}

\boxed {x = -1}

Therefore, the value of x is -1.

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What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?
Natali5045456 [20]

Answer:

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6x+y=-5

Step-by-step explanation:

Given:  

Let,  

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:  

Equation of Line  that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?  

Solution:  

x-6y=42    ..................Given

which can be written as

y=mx+c

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So,

Product of slopes = - 1

m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

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(y-y_{1})=m(x-x_{1})

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(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

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