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MA_775_DIABLO [31]

3 years ago

13

The minimum wage in 2003 was $5.15. This was w more than the minimum wage in 1996. Write an expression for the minimum wage in 1

996.

1 answer:

bekas [8.4K]3 years ago

8 0

$5.15 - w = minimum wage in 1996

(if that wasn't what you were looking for then comment what you really wanted)

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what is the opportunity cost of buying a $.75 soda every school day for three years instead of drinking water? assume you are in

11Alexandr11 [23.1K]

Answer:

I don't understand your question

4 0

3 years ago

Point A is located at (4, 8) and point B is located at (14, 10) . What point partitions the directed line segment AB⎯⎯⎯⎯⎯

andrew11 [14]

The 1:3 ratio means that the distance from A to the point is 1/4 of the distance from A to B.

The difference of y-coordinates is 10-8 = 2. 1/4 of that is 2·1/4 = 1/2, so the point of interest will have y-coordinate 8 + 1/2 = 8 1/2. This apparently corresponds to the first selection:

... (6 1/2, 8 1/2)

7 0

3 years ago

Given <img src="https://tex.z-dn.net/?f=f%28x%29%20%3Dx%5E2%20-6x%2B8%20and%20g%28x%29%20%3Dx-2" id="TexFormula1" title="f(x) =x

Eva8 [605]

For this case we have the following functions:

$f (x) = x ^ 2-6x + 8\\g (x) = x-2$

We must subtract the functions:

$f (x) -g (x) = x ^ 2-6x + 8- (x-2)\\f (x) -g (x) = x ^ 2-6x + 8-x + 2\\f (x) -g (x) = x ^ 2-7x + 10$

We build a table of values for $x = 0,1,2,3.$

$x = 0, f (x) -g (x) = 0 ^ 2-7 (0) + 10 = 10\\x = 1, f (x) -g (x) = 1 ^ 2-7 (1) + 10 = 1-7 + 10 = 4\\x = 2, f (x) -g (x) = 2 ^ 2-7 (2) + 10 = 4-14 + 10 = 0\\x = 3, f (x) -g (x) = 3 ^ 2-7 (3) + 10 = 9-21 + 10 = -2$

Answer:

$f (x) -g (x) = x ^ 2-7x + 10$

8 0

3 years ago

The cost CC (in dollars) of making nn watches is represented by C=15n+85C=15n+85. How many watches are made when the cost is $38

dangina [55]

$\bf \stackrel{cost}{C}=15\stackrel{watches}{n}+85\qquad \boxed{C=385}\qquad \stackrel{cost}{385}=15n+85
\\\\\\
380=15n\implies \cfrac{380}{15}=n\implies \cfrac{76}{3}=n\implies 25\frac{1}{3}=n$

so, 25 whole watches and hmmmm just the wristband of another maybe.

5 0

3 years ago

Find the numerical value of the log expression. \log a=7\hspace{15px} \log b=10\hspace{15px} \log c=3 loga=7logb=10logc=3 \log \

bija089 [108]

Answer:

32

Step-by-step explanation:

$\log a=7\hspace{15px} \log b=10\hspace{15px} \log c=3\\\\ \log \dfrac{a^8c^2}{b^3}=8\log{a}+2\log{c}-3\log{b}=(8)(7)+(2)(3)-(3)(10)\\\\=56+6-30=\boxed{32}$

__

The applicable rules of logarithms are ...

log(ab/c) = log(a) +log(b) -log(c)

log(a^b) = b·log(a)

6 0

3 years ago