if you add a negitive to a positive its like subtracting like 20 - (-30) (that would be -10) for your question its 0.6
Answer:
V ( Vcos 60° , Vsin60°) or V ( 2, 2√3)
Step-by-step explanation:
A vector and its components form a right triangle, then we need to get trigonometric functions ( sin and cos) of the angle of the module with x-axis
π/3 = 180⁰/3 = 60⁰ Angle between vector and positive x-axis
and sin 60⁰ = √3 /2 cos 60⁰ = 1/2
Let call V(x) component of vector v in x-axis, and V(y) component of vector v in y-axis then
V(x) = |v|*cos 60⁰ ⇒ V(x) = |v|*1/2 ⇒ V(x) = 4*1/2 ⇒ V(x) = 2
And
V(y) = |v|*sin 60⁰ ⇒ V(y) = |v|*√3/2 ⇒ V(y) = 4*√3/2 V(y) = 2*√3
V = (Vx,Vy) V ( Vcos 60° , Vsin60°) V ( 2, 2√3)
Answer:
Area of shaded region = 28 in^2
Step-by-step explanation:
Area of rectangle = 8 x 5 = 40 in^2
Area of triangle = 1/2 x 8 x 3 = 12 in^2
Area of shaded region = 40 in^2 - 12 in^2 = 28 in^2
Answer:
20 ton
Step-by-step explanation:
We created a system of two separate equations to answer these questions.
"y" will be the total cost to transport the sugar
"x" will be the amount of sugar transported
Therefore, we have to:
y = 3995 + 225.50 * x
y = 6500 + 100.25 * x
We must establish these equations equal to each other because it asks how much of x is necessary to make the same amount of y, therefore:
3995 + 225.50 * x = 6500 + 100.25 * x
solved we have:
225.50 * x - 100.25 * x = 6500 - 3995
125.25 * x = 2505
x = 2505 / 125.25
x = 20
which means that when the amount of sugar transported is 20 tons, the price is the same