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USPshnik [31]
3 years ago
12

Which polynomial function has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1?

Mathematics
2 answers:
Gala2k [10]3 years ago
7 0
Root of 2i also means there is a root of -2i
Root of 3i also means there is a root of -3i

Factors will be (x^2 + 4)(x^2 + 9).
Multiply this out to get the polynomial:
x^4 + 13x^2 + 36
vampirchik [111]3 years ago
7 0

Answer:


Step-by-step explanation:

f(x) = (x + 2i)(x + 3i)(x – 2i)(x – 3i)

Choice D.

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the perimeter of a rectangle is 70 cm . if the ratio of the width to the length is 2:5 what is the width ?
denpristay [2]

Answer:

width = 10 cm

Step-by-step explanation:

the ratio of width to length is 2 : 5 = 2x : 5x ( x is a multiplier )

the perimeter (P) of a rectangle is calculated as

P = 2 × width + 2 × length

given P = 70 then

2(2x) + 2(5x) = 70

4x + 10x = 70

14x = 70 ( divide both sides by 14 )

x = 5

Then

width = 2x = 2 × 5 = 10 cm and length = 5x = 5 × 5 = 25 cm

5 0
2 years ago
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(-4,2) (2-3) midpoint
Sedbober [7]

Answer:

(-1, -1/2)

Step-by-step explanation:

use the midpoint formula(x1+x2/2, y1+y2/2)

-4+2/2, 2+-3/2

-4+2=-2/2=-1

2+-3=-1/2

(-1, -1/2)

3 0
3 years ago
Simplify (6-4i)-(3+2i)
marissa [1.9K]
Group like numbers
 6-3-4i-2i
3-6i
7 0
3 years ago
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A man weighing 800 N is hanging from a 2 mm diameter titanium wire with a cross-section of 3 x 10^-6 m^2. Will the wire break?
DENIUS [597]

Answer:

Since stress is greater than ultimate strength, the wire will break.

Step-by-step explanation:

The titanium wire is experimenting an axial load. Ultimate strength equals 2.20\times 10^{8}\,Pa. The wire shall break if and only if stress is at least equal to ultimate strength. The equation for axial stress (\sigma), measured in pascals, in the wire with circular cross-section is:

\sigma = \frac{4\cdot F}{\pi\cdot D^{2}} (1)

Where:

F - Axial force, measured in newtons.

D - Cross-section diameter, measured in meters.

Please notice that axial force is the weight of the man hanging from wire.

If we know that F = 800\,N and D = 0.002\,m, then the axial stress experimented by the titanium wire is:

\sigma = \frac{4\cdot (800\,N)}{\pi\cdot (0.002\,m)^{2}}

\sigma \approx 2.546\times 10^{8}\,Pa

Since stress is greater than ultimate strength, the wire will break.

3 0
2 years ago
What does 4.23×9 equal
nata0808 [166]
<span>4.23 times 9 equals 38.07 :)</span>
8 0
3 years ago
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