Which polynomial function has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1?
2 answers:
Root of 2i also means there is a root of -2i
Root of 3i also means there is a root of -3i
Factors will be (x^2 + 4)(x^2 + 9).
Multiply this out to get the polynomial:
x^4 + 13x^2 + 36
Answer:
Step-by-step explanation:
f(x) = (x + 2i)(x + 3i)(x – 2i)(x – 3i)
Choice D.
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Answer:
a) 3x + ky = 8
ky = 8 - 3x
x – 2ky = 5
x - 2(8 - 3x) = 5
x - 16 + 6x = 5
7x = 21
x = 3 (shown)
b) x-2ky = 5
sub x = 3, y = 1/2
3-2k(1/2) = 5
-2k = 2
k = -1