3 years ago

Which polynomial function has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1?

2 answers:

7 0

Root of 2i also means there is a root of -2i
Root of 3i also means there is a root of -3i

Factors will be (x^2 + 4)(x^2 + 9).
Multiply this out to get the polynomial:
x^4 + 13x^2 + 36

vampirchik [111]3 years ago

7 0

Answer:

Step-by-step explanation:

f(x) = (x + 2i)(x + 3i)(x – 2i)(x – 3i)

Choice D.

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