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amm1812
3 years ago
13

I am a number between 60 and 100 My ones digit is 2 less than my tens digit. I am a prime number. What number am I?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0
97.

9 has a 9 in its tens digit, and a 7 in its ones digit, which is 2 less than 9.
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Please help and thank you
kondaur [170]

Answer:

Step-by-step explanation:

Let's see how well I can explain this. \frac{\pi}{6} is the same as a 30 degree angle which is in quadrant 1. If you picture the unit circle, right in the center of it is the origin. If you draw a straight line from 30 degrees and through the center (the origin), you will automatically "connect" with the reference angle of 30 (this is true for ALL angles on the unit circle). This puts us in quadrant 3. In quadrant 3, x is negative and so is y. So the terminal point of the reference angle for 30 degrees has the same exact values, but both of them are negative (again, because both x and y are negative in quadrant 3). I can't see your choices but the one you want looks like this:

(-\frac{\sqrt{3} }{2},-\frac{1}{2})

3 0
2 years ago
Tom has a recipe for punch that calls for 1/2 gallon of fruit drink, how much fruit drink will tom need to make 5/2 batches of t
Hunter-Best [27]

Answer:

Tom will need \dfrac{5}{4} gallons of fruit drink.

Step-by-step explanation:

Hint- This question can be solved by unitary method.

Tom has a recipe for punch that calls for \dfrac{1}{2} gallon of fruit drink.

i.e for 1 batch of the punch Tom needs \dfrac{1}{2} gallon of fruit drink.

For \dfrac{5}{2} batch of the punch Tom needs \dfrac{1}{2}\times \dfrac{5}{2}=\dfrac{5}{4} gallons of fruit drink.

Therefore, Tom will need \dfrac{5}{4} gallons of fruit drink.

4 0
3 years ago
Solve for x.<br> -7 &gt; 13 - 50<br> Enter your answer as an inequa
Svet_ta [14]
-7>-63 because the more negative the number the less the value
6 0
2 years ago
2 m3 of soil containing 35% sand was mixed into 6 m3 of soil containing 15% sand. what is the sand content of the mixture?
jekas [21]
Answer is: 1.6 m3 of sand
4 0
3 years ago
This is the third time and i a really annoyed as i am having my time wasted and points
muminat

Answer: A) 20.9 ; B) 34years

Step-by-step explanation:

Given the following :

AGE (X) - - - - - - - 19 - -20 - - - 21 - - - 22 - - - 23

FREQUENCY (F) - 2 - - 3 - - - - 1 - - - - 4 - - - - 1

A)

MEAN(X) = [AGE(X) × FREQUENCY (F)] ÷ SUM OF FREQUENCY

F*X = [(19 * 2) + (20 * 3) + ( 21 * 1)+(22 * 4)+(23 * 1)]

= 38 + 60 +21 + 88 + 23 = 230

SUM OF FREQUENCY = 2 + 3 + 1 + 4 + 1= 11

MEAN(X) = 230 / 11

X = 20.9

B)

WHEN A NEW PLAYER WAS ADDED :

MEAN (X) = 22

Let age of new player = y

Sum of Ages = 19 + 19 +20 + 20 + 20 + 21 + 22 + 22 + 22 + 22 + 23 + y

Number of players = 11 + 1 = 12

Mean(x) = sum of ages / number of players

New mean (x) = 22

x = (230 + y) / 12

22 = (230 + y) / 12

Cross multiply

264 = 230 + y

y = 264 - 230

y = 34 years

4 0
3 years ago
Read 2 more answers
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