You can answer this question by plugging the given values into point-slope form, which is y - y_{1} = m (x - x_{1}). M will represent slope and x_{1} and y_{1} will represent the x and y coordinates.
y - y_{1} = m (x - x_{1}) Substitute in the values
y - (-5) = 4 (m - 4) Cancel out the -(-5)
y + 5 = 4 (m - 4) Use the Distributive Property
y + 5 = 4m - 16 Subtract 5 from both sides
y = 4m - 21
Solution:
As given Square L M NO is dilated by a scale factor of two about the center of the square to create square L'M'N'O'.
Original line of Dilation = Along P Q
New Dilated line = P'Q'
As scale factor > 1
1. Image Size > Pre image size
2. The two images will be similar.
3. Length of Dilated Line P' Q' = 2 × Length of PQ
As you can see from the diagram drawn below, Dilated line P'Q' will contain the point P and Q.
All four points P,Q,Q',P' are collinear , lie in the same line.
Option (2) dilated line P'Q' will contain the points P and Q is true.
Answer:
Step-by-step explanation:
The ratio of the angle is how the angle relates to each other. Let's say that we try to relate Angle A, B, C and get 1 : 3 : 5. That means Angle B is three times Angle A and Angle C is 5 times Angle A
Thus we get the equation:
A
B = 3A
C = 5A
A + B + C = 180, since all the angles of the triangle is equal to 180 degrees
A + 3A + 5A = 180
9A = 180
A = 20 --> B = 3A = 60 --> C = 5A = 100
So Angle A is 20 degrees, Angle B is 60 degrees, and Angle C is 100 degrees.
Hope that helps!
Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:

We substitute x=161.4 ,
, and
to get:

From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
It is best to use mental math with some equations (5x5 or something that is easy enough that work does not have to be shown 10 dived by 5