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velikii [3]
3 years ago
11

Lisa wants to cover the top of the lid in beads. She has enough beads to cover 42 square centimeters. Find the area of the lid.

Can Lisa cover the top in beads?
Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0
Well this depends on the the the size of the cover
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An airplane descends 2.8 miles to an elevation of 5.85 miles. Find the elevation of the plane before an airplane descends 2.2 mi
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Answer:

8.05 miles

Step-by-step explanation:

If it descended 2.2 miles to 5.85 miles then that means it was at 5.85 + 2.2 miles before its descent.

5.85 + 2.2 = 8.05

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The distribution of heights for adult men in a certain population is approximately normal with mean 70 inches and standard devia
KengaRu [80]

Answer:

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]

Step-by-step explanation:

I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1

If X is the distribuition of heights, then we want z such that P(X > z) = 0.1. We will take W, the standarization of X, wth distribution N(0,1)

W = \frac{X-\mu}{\sigma} = \frac{X-70}{4}

The values of the cumulative distribution function of W, denoted by \phi , can be found in the attached file. Lets call y = \frac{z-70}{4} . We have

0.1 = P(X > z) = P(\frac{X-70}{4} > \frac{z-70}{4}) = P(W > y) = 1-\phi(y)

Thus

\phi(y) = 1-0.1 = 0.9

by looking at the table, we find that y = 1.28, therefore

\frac{z-70}{4} = 1.28\\z = 1.28*4+70 = 75.12

The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is 70- (75.12-70) = 64.88.

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12] .

Download pdf
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