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just olya [345]
3 years ago
12

Which expressions are equivalent to RootIndex 3 StartRoot 128 EndRoot Superscript x? Select three correct answers.

Mathematics
2 answers:
vodka [1.7K]3 years ago
5 0

Answer:

<h3>- 128 Superscript StartFraction 3 Over x EndFraction </h3><h3>- (4RootIndex 3 StartRoot 2 EndRoot)x </h3><h3>- (4 (2 Superscript one-third Baseline) ) Superscript x</h3><h3>Step-by-step explanation:</h3>

Given the indicinal equation (\sqrt[3]{128} )^{x}\\

According to one of the law of indices,

(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}

Applying this law to the question;

(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )

The following are therefore true based on the following calculation

128 Superscript StartFraction 3 Over x EndFraction

(4RootIndex 3 StartRoot 2 EndRoot)x

(4 (2 Superscript one-third Baseline) ) Superscript x

Rzqust [24]3 years ago
4 0

Answer:

Options B, C, and D on edgenui.ty

Step-by-step explanation:

See the work  down above ^^^

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Paco makes $24.00 in 2 hours. So, in 1 hour, he would make 24/2 = 12.

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In a circle with a radius of 6 ft, an arc is intercepted by a central angle of 3π/2 radians.
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Answer:

Option 4 - L=9\pi ft.

Step-by-step explanation:

Given : In a circle with a radius of 6 ft, an arc is intercepted by a central angle of 3π/2 radians.

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Solution :

Length of an arc is given by:

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Answer:

The 4th term is 7

Step-by-step explanation:

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C(n)=C(n-1)\frac{1}{2}

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For n=2

C(2)=C(1)\frac{1}{2}

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