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monitta
3 years ago
7

Please helppp, thank you

Mathematics
2 answers:
Molodets [167]3 years ago
8 0

41/600= x/1700

Cross multiply

41 times 1700=600x

69700=600x

X=116

yulyashka [42]3 years ago
6 0
My prediction would be 1,659 defective brakes. I hope this helps you
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What is the product?<br> 3 x [1 -4 5 -7]
Roman55 [17]

This looks like scalar matrix multiplication. The idea here is to multiply the scalar 3 by each item inside the matrix.

Doing so leads to the answer [3   -12    15    -21]

Side note: I'm assuming the matrix given to you has 1 row and 4 columns.

6 0
3 years ago
On a trip, you had to change your money from dollars to British pounds. 
irga5000 [103]

Answer:

560/800 = 0.7 pounds per dollar

6 0
3 years ago
Read 2 more answers
Please help me out!!!
professor190 [17]

Answer:

<u>416 square centimeters</u>

Step-by-step explanation:

Formula for finding area of a trapezoid :

<u>A = 1/2 x (a + b) x h</u>

  1. a and b = parallel sides of the trapezoid
  2. h = height of the trapezoid

Solving :

  • A = 1/2 x (38 + 14) x 16
  • A = 8 x 52
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3 0
2 years ago
Read 2 more answers
Consider the differential equation:
Wewaii [24]

(a) Take the Laplace transform of both sides:

2y''(t)+ty'(t)-2y(t)=14

\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s

where the transform of ty'(t) comes from

L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)

This yields the linear ODE,

-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s

Divides both sides by -s:

Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}

Find the integrating factor:

\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C

Multiply both sides of the ODE by e^{3\ln|s|-s^2}=s^3e^{-s^2}:

s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}

The left side condenses into the derivative of a product:

\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}

Integrate both sides and solve for Y(s):

s^3e^{-s^2}Y(s)=7e^{-s^2}+C

Y(s)=\dfrac{7+Ce^{s^2}}{s^3}

(b) Taking the inverse transform of both sides gives

y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that \frac{7t^2}2 is one solution to the original ODE.

y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7

Substitute these into the ODE to see everything checks out:

2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14

5 0
3 years ago
How do you find the measure of ECF?
tigry1 [53]

Answer:

37°

Step-by-step explanation:

∠ECF= ∠ACG

∠ACG= 90° - ∠GAC= 90° - 53°= 37°

6 0
3 years ago
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