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Oksi-84 [34.3K]
3 years ago
9

What can you say about the end of behavior of the function f(x)=-4x^6+6x^2-52?

Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0
For end behavior, we need to consider 2 things: the highest exponent, and the coefficient of the highest exponent.
the highest exponent is 6, an even number, which means that the end behaviors will both be ∞ or -∞.
Since the coefficient is -4, a negative number, the end behaviors will both be -∞.
As x→ -∞, f(x)→ -∞. As x→ ∞, f(x)→ -∞.
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What is "a" if B=<br>is a singular matrix<br>| 2<br>2 a​
Inessa05 [86]

Answer:

The value of a=4

Step-by-step explanation:

Given the matrix

B=\begin{pmatrix}1\:&\:2\:\\ \:\:\:2\:&\:a\end{pmatrix}

  • A matrix is singular if its determinent is zero.

so solving the matrix B by taking its determinant to get the value a

\det \begin{pmatrix}1&2\\ 2&a\end{pmatrix}=0

as according to determinant formula

\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc

 1\cdot \:a-2\cdot \:2=0    

  a-4=0

   a=4          

Therefore, the value of a=4

7 0
3 years ago
11) The sum of two numbers is 25. The difference of two numbers is 3.
kupik [55]

Answer:

11) 14 and 11

Step-by-step explanation:

i can't help in number 12 , sorry !

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4 years ago
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SashulF [63]
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3 years ago
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16. In a group of 68 students, each student is registered for at least one of three classes – History, Math and English. Twenty-
sergey [27]

Answer:

Step-by-step explanation:

Total number of students = 68

Let history = H

Maths = M

English = E

n(H) = 25

n(M) = 25

n(E) = 34

n(HnMnE) = 3

Total = n(H) + n(M) + n(E) - people in exactly two groups + 2(people in exactly 3 groups) + people in none of the groups

68 = 25 + 25 + 34 - people in exactly two groups - 6 +0

68 = 84 -6 - people in exactly two groups

68 = 78 - people in exactly two groups

People in exactly two groups = 78 - 68

= 10

OR

From the venn diagram, people in exactly two groups are represented by x, y and z

Total = 25 - x - y - 3 + 25 - x - z - 3 + 34 - y - z - 3 + x + y + z + 3

68 = 50 - x - 3 + 34 - y - z - 3

68 = 84 - 6 - x - y - z

68 = 78 - x - y - z

68 - 78 = - x - y - z

-10 = -(x + y + z)

x+y+z = -10/-1

x+y+z = 10

The number of students that registered for exactly two courses = 10

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