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3 years ago

Can i get help plz this question rlly hard

Mathematics

2 answers:

Artyom0805 [142]3 years ago

8 0

Answer:

1890

Step-by-step explanation:

erma4kov [3.2K]3 years ago

3 0

Answer:

I believe your answer is 1512

Step-by-step explanation:

4.2 x 2 = 8.4 this is the area, each inch is equal to 15 feet, there are 180 inches in 15 feet. so 8.4 x 180 = 1512.

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Jesse earns $12.62 an hour, plus she earns overtime for hours exceeding 40 hours per week. What is her gross weekly pay for work

san4es73 [151]

40(12.62) + 7(12.62(1.5)) = 504.80 + 7(18.93) = 504.80 + 132.51 =
637.31 <===

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4 years ago

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Solve 3x-2y=15 for y?

Nikitich [7]

Answer:

y=3x-15

Step-by-step explanation:

3x-2y=15

+2y +2y

3x=15+2y

-15 -15

y=3x-15

7 0

3 years ago

Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

3 years ago

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Solve the inequality 5(2h + 8) < 60

Ad libitum [116K]

Step-by-step explanation:

5(2h+8) <60

10h +40< 60

10h + 40-40 < 60-40

10h < 20

10h/10 < 20/10

h < 2

7 0

3 years ago

Write this statement as a conditional in if-then form:. . All triangles have three sides.. . (1 point). If a triangle has three

ehidna [41]

The <u>correct answer</u> is:

<span>If a figure is a triangle, then it has three sides.

Explanation:

A conditional is an if-then statement. The part after "if" is called the hypothesis; the part after "then" is called the conclusion.

We know that triangles have 3 sides. We will start out with "if a figure is a triangle"; we end with "then it has three sides."

This is a true conditional statement.</span>

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4 years ago

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