What values for theta (0 theta 2pi) satisfy the equation 2 sin theta cos theta + sqrt 3 cos theta?
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Slope is 1/2. The equation to solve it is y2-y1 / x2-x1. I hope you understand it now :)
Neato
assuming you mean
remember
in form
a is leading coficient
(h,k) is vertex
k will be the minimum or max value of the function
if a is positive, then the parabola opens up and k is minimum
if a is negative, then the parabola opens down and k is max
given
a is negative
the parabola opens down and k is the max value
it is -3
the max value is -3, which occors at x=2
g(2)=-3 is max
assuming you mean
remember
in form
a is leading coficient
(h,k) is vertex
k will be the minimum or max value of the function
if a is positive, then the parabola opens up and k is minimum
if a is negative, then the parabola opens down and k is max
given
a is negative
the parabola opens down and k is the max value
it is -3
the max value is -3, which occors at x=2
g(2)=-3 is max