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3 years ago

Find the value of y in the equation 3/y-2=8

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

8 0

H e r e i s t h e a n s w e r !

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Answer asap !!!!!!

GaryK [48]

Value of r is -4

Step-by-step explanation:

We are given points (-1,-6) and (0,r) on line and slope of line is -2. We need to find value of r.

Using slope formula when two points are given:

$Slope=\frac{y_2-y_1}{x_2-x_1}$

Where $x_1=-1,\,\,y_1=-6,\,\,x_2=0,\,\,y_2=r$

Putting values:

$2=\frac{r-(-6)}{0-(-1)} \\2=\frac{r+6}{0+1} \\2=\frac{r+6}{1} \\2=r+6$

Adding -6 on both sides:

$2-6=r\\-4=r$

So, Value of r is -4

Keywords: Slope of line

Learn more about Slope of line at:

#learnwithBrainly

4 0

3 years ago

What are the first trillion digits of pi?

gregori [183]

Answer:

3.14159265359

Step-by-step explanation:

Most people just use 3.14 for math though

8 0

3 years ago

What percent increase is 1/3 to 1/6

r-ruslan [8.4K]

Answer:

50% increase

Step-by-step explanation:

half of 6 is 3 thus 50%, and vise versa.

4 0

2 years ago

What value(s) of x make the equation x2 - 18x + 81 = 0 true?

mel-nik [20]

We can factorise this to get (x-9)(x-9). To find the value, each bracket needs to equal 0, so the value would be x=9

5 0

3 years ago

Read 2 more answers

Verify which of the following are identities.

-Dominant- [34]

Answer:

Only the second equation is an identity

Step-by-step explanation:

$8 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=8 \csc(\theta)$

$\tan^2(\theta)\csc^2(\theta)=\sec^2(\theta)$

<u>You can confirm it: </u>

$\frac{\sin^2(\theta)}{\cos^2(\theta)}\cdot \frac{1}{\sin^2(\theta)}= \frac{1}{cos^2(\theta)}= \sec^2(\theta)$

<u>Therefore</u>

$8 \frac{\sec^2(\theta)}{\sec(\theta)} =8 \csc(\theta)$

$8 \frac{\sec(\theta)}{1} =8 \csc(\theta)$

$8\sec(\theta)=8\csc(\theta)$

<h2>It is not an Identity</h2>

<u>Let's the second one</u>

$13 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=13\sec(\theta)$

In this case, we already performed the calculations, so it is true. It is an Identity.

3 0

2 years ago